计算机等级考试二级VB常用算法(4)：进制转化

解题技巧
         进制转化的原理要清楚,同时编写代码时候要留意16进制中的A－F字符的处理。

 2、实战练习

1)        补充代码（2002秋二（9））
         本程序是把给定的二进制整数转换为八进制整数。
                  Private Sub Command1_Click()
                           Dim a As String, b As String, c As String
                           Dim L As Integer, m As Integer, n As Integer
                           a = InputBox("请输入一个二进制数", "输入框")
                              （1）    
                           a = String(L, "0") & a
                              （2）    
                           For m = 1 To n / 3
                             b = Mid(a, 3 * m - 2, 3)
                                 （3）     
                           Next m
                           Text1.Text = c
                  End Sub

                   Private Function zh(s As String) As String
                           Dim i As Integer, n As Integer, p As Integer
                           p = 1
                           For i = 2 To 0 Step -1
                                       （4）     
                              p = p + 1
                           Next i
                           zh = Str(n)
                  End Function

2)        补充代码（2001春二（7））
         下面程序是把给定的16进制正整数转换为10进制数。
                  Option Explicit

                   Private Sub Form_Click()
                           Dim St As Integer， Dem As Long
                           St=InputBox("输入一个十六进制数")
                           Dem=Convert(St)
                           Print St; ">="; Dem
                  End Sub

                   Private Function Convert(S As String)As Long
                           Dim N As Integer， I As Integer，Substring As String*1
                           Dim P As long， K As Long，Asc1 As Integer
                           N=  （1）  
                           P=16^N
                           For I=1 To N
                                    P=P/16
                                    Substring=  （2）  
                                    Select Case Substring
                                             Case "0" To "9"
                                                      K=K+P*Val(Substring)
                                             Case   （3）  
                                                      Asc1=Asc(Substring)-Asc("A")+10
                                                        （4）  
                                    End Select
                           Next I
                             （5）  

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